4a^2+4+a^2+16=0

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Solution for 4a^2+4+a^2+16=0 equation: 



4a^2+4+a^2+16=0

We add all the numbers together, and all the variables

5a^2+20=0

a = 5; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·5·20
Δ = -400
Delta is less than zero, so there is no solution for the equation

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